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In the mathematical subfield of numerical analysis, a Bernstein polynomial, named after Sergei Natanovich Bernstein, is a polynomial in the Bernstein form, that is a linear combination of Bernstein basis polynomials. A numerical stable way to evaluate polynomials in Bernstein form is de Casteljau's algorithm. Polynomials in Bernstein form were first used by Bernstein in a constructive proof for the Stone-Weierstrass approximation theorem. With the advent of computer graphics Bernstein polynomials, restricted to the interval [0,1], became important in the form of Bézier curves. Definition
The n+1 Bernstein basis polynomials of degree n are defined as The Bernstein basis polynomials of degree n form a basis for the vector space Πn of polynomials of degree n. A linear combination of Bernstein basis polynomials is called Bernstein polynomial or polynomial in Bernstein form of degree n. The coefficients βν are called Bernstein coefficients or Bézier coefficients.
Notes The Bernstein basis polynomials have the following properties - bν,n(x) has a root with multiplicity ν at point x = 0
- bν,n(x) has a root with multiplicity n − ν at point x = 1
- bν,n(x) ≥ 0 if x in [0,1]
- bν,n(x) has a global maximum at x = ν/n
- b’ν,n(x) = n [bν-1,n-1(x) - bν,n-1(x)]
- bν,n(x) = 0, if ν < 0 or ν > n
The Bernstein basis polynomials of degree n form a partition of unity Example The first few Bernstein basis polynomials are Approximating continuous functions Let f(x) be a continuous function on the interval [0, 1]. Consider the Bernstein polynomial It can be shown that uniformly on the interval [0, 1]. This is a stronger statement than the proposition that the limit holds for each value of x separately; that would be pointwise convergence rather than uniform convergence. Specifically, the word uniformly signifies that Bernstein polynomials thus afford one way to prove the Stone_Weierstrass approximation theorem that every real_valued continuous function on a real interval [a,b] can be uniformly approximated by polynomial functions over R.
Proof Suppose K is a random variable distributed as the number of successes in n independent Bernoulli trials with probability x of success on each trial; in other words, K has a binomial distribution with parameters n and x. Then we have the expected value E(K/n) = x. Then the weak law of large numbers of probability theory tells us that Because f, being continuous on a closed bounded interval, must be uniformly continuous on that interval, we can infer a statement of the form Consequently -
And so the second probability above approaches 0 as n grows. But the second probability is either 0 or 1, since the only thing that is random is K, and that appears within the scope of the expectation operator E. Finally, observe that E(f(K/n)) is just the Bernstein polynomial Bn(f,x).
See also
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