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Encyclopedia > Decimal representation
It has been suggested that this article or section be merged with decimal. (Discuss)


A decimal representation of a positive real number r is an expression of the form Wikipedia does not have an article with this exact name. ... Decimal, or less commonly, denary, usually refers to the base 10 numeral system. ... In mathematics, the real numbers are intuitively defined as numbers that are in one-to-one correspondence with the points on an infinite line—the number line. ...

r=sum_{i=0}^infty frac{a_i}{10^i}

where a0 is a nonnegative integer and a_1, a_2, dots are integers satisfying 0leq a_ileq 9, usually written more briefly as follows:

r=a_0.a_1 a_2 a_3dots.

Contents


Finite decimal approximations

Any real number can be approximated to any desired degree of accuracy by rational numbers with finite decimal representations. In mathematics, a rational number (or informally fraction) is a ratio or quotient of two integers, usually written as the vulgar fraction a/b, where b is not zero. ...


Assume xgeq 0. Then for every integer ngeq 1 there is a finte decimal r_n=a_0.a_1a_2cdots a_n such that

r_nleq x < r_n+frac{1}{10^n}.,

Proof:


Let S be the set of all nonnegative integers leq x. Then S is nonempty, since 0in S, and S is bounded above by x. Therefore S has a supremum, say a_0 = sup S. It is easily verified that a_0in S, so a0 is a nonnegative integer. We call a0 the greatest integer in x, and we write a_0 = lfloor xrfloor. Clearly, we havea_0leq x<a_0+1.


Now let a_1 = lfloor 10x-10a_0rfloor, the greatest integer in 10x − 10a0. Since 0leq 10x-10a_0 =10(x-a_0)<10, we have 0leq a_1leq 9 and a_1leq 10x-10a_0 < a_1+1. In other words, a1 is the largest integer satisfying the inequalities

a_0+frac{a_1}{10}leq x < a_0 + frac{a_1+1}{10}.

More generally, having chosen a_1,dots,a_{n-1} with 0leq a_ileq 9, let an be the largest integer satisfying the inequalities

a_0+frac{a_1}{10}+cdots +frac{a_n}{10^n}leq x < a_0+frac{a_1}{10}+cdots +frac{a_n+1}{10^n}.,

Then 0leq a_n leq 9 and we have

r_nleq x < r_n+frac{1}{10^n},,

where r_n=a_0.a_1a_2cdots a_n.


It is easy to verify that x is actually the supremum of the set of rational numbers r_1, r_2, dots.


Verification that a0S

By the approximation property of the supremum of a set of real numbers, for every z>0, there exists x in S such that a0z < x. Therefore, a_0 leq x and then a_0in S for xleq a_0. In mathematics, the supremum of an ordered set S is the least element that is greater than or equal to each element of S. Consequently, it is also referred to as the least upper bound (also lub and LUB). ...


Verify that x is the supremum of the set of rational numbers r1, r2, ...

For every natual number i, r_ileq x, or x is the upper bound of the set of rational numbers r1,r2,.... Suppose that there is a real number y such that r_ileq y for every natural number i and y < x. Thus, 0 < xy < 1 / 10n and then 0<x-yleq 0. This is a contradiction. Therefore, x is the least upper bound, or the supremum. In mathematics, the supremum of an ordered set S is the least element (not necessarily in S) which is greater than or equal to each element of S. Consequently, it is also referred to as the least upper bound. ...


Finite decimal representions

The decimal expansion of x will end in zeros(or in nines) if, and only if, x is a rational number whose denominator is of the form 2n5m, where m and n are nonnegative integers.


Proof:


If the decimal expansion of x will end in zeros, or x=sum_{i=0}^nfrac{a_i}{10^i}=sum_{i=0}^n10^{n-i}a_i/10^n for some n, then the denominator of x is of the form 10n = 2n5n.


Conversely, if the denominator of x is of the form 2n5m, x=frac{p}{2^n5^m}=frac{2^m5^np}{2^{n+m}5^{n+m}}= frac{2^m5^np}{10^{n+m}} for some p. While x is of the form p/10k, p=sum_{i=0}^{n}10^ia_i for some n. By x=sum_{i=0}^n10^{n-i}a_i/10^n=sum_{i=0}^nfrac{a_i}{10^i}, x will end in zeros.


 

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