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Encyclopedia > Projective transformation

A projective transformation is a transformation used in projective geometry: it is the composition of a pair of perspective projections. It describes what happens to the perceived positions of observed objects when the point of view of the observer changes. Projective transformations do not preserve sizes or angles but do preserve incidence and cross-ratio: two properties which are important in projective geometry. A projective transformation can also be called a projectivity. In mathematics, a transformation in elementary terms is any of a variety of different functions from geometry, such as rotations, reflections and translations. ... Projective geometry is a non-metrical form of geometry that emerged in the early 19th century. ... Perspective projection is a type of drawing that graphically approximates on a planar (two-dimensional) surface (e. ... In geometry, the relations of incidence are those such as lies on between points and lines (as in point P lies on line L), and intersects (as in line L1 intersects line L2, in three-dimensional space). ... In mathematics, the cross-ratio cr( w, x, y, z ) of an ordered quadruple of complex numbers (which may be real numbers) is Cross-ratios are preserved by linear fractional transformations, i. ...


A projective transformation can be in the (real) one-dimensional projective line RP1, the two-dimensional projective plane RP2, and the three-dimensional projective 3-space RP3. In mathematics, a projective line is a one-dimensional projective space. ... Projective plane - Wikipedia, the free encyclopedia /**/ @import /skins-1. ...

Contents

Transformations on the projective line

Let X be a point on the x-axis. A projective transformation can be defined geometrically for this line by picking a pair of points P, Q, and a line m, all within the same x-y plane which contains the x-axis upon which the transformation will be performed.


Draw line l through points P and X. Line l crosses line m at point R. Then draw line n through points Q and R: line n will cross the x-axis at point T. Point T is the transform of point X [Paiva].


Points P and Q represent two different observers, or points of view. Point R is the position of some object they are observing. Line m is the objective world which they are observing, and the x-axis is the subjective perception of m.


Analysis

The above is a synthetic description of a one-dimensional projective transformation. It is now desired to convert it to an analytical (Cartesian) description. Synthetic geometry is a descriptive term that identifies a methodology of geometry which makes use of theorems and synthetic observations to create theorems or solve problems, as opposed to analytic geometry which uses algebra, numbers, computations to draw theorems or solve problems. ... Analytic geometry, also called coordinate geometry and earlier referred to as Cartesian geometry, is the study of geometry using the principles of algebra. ...


Let point X have coordinates (x0,0). Let point P have coordinates (Px,Py). Let point Q have coordinates (Qx,Qy). Let line m have slope m (m is being overloaded in meaning).


The slope of line l is

,

so an arbitrary point (x,y) on line l is given by the equation

{y over x - x_0} = {P_y over P_x - x_0},
y = {P_y over P_x - x_0} (x - x_0). qquad qquad (1)

On the other hand, any point (x,y) on line m is described by

y = m x + b. qquad qquad (2)

The intersection of lines l and m is point R, and it is obtained by combining equations (1) and (2):

m x + b = {P_y x over P_x - x_0} - {P_y x_0 over P_x - x_0}.

Joining the x terms yields

left( {P_y over P_x - x_0} - m right) x = b + {P_y x_0 over P_x - x_0}

and solving for x we obtain

x_1 = {b (P_x - x_0) + P_y x_0 over P_y - m (P_x - x_0)}.

x1 is the abscissa of R. The ordinate of R is

y_1 = m left[ {b (P_x - x_0) + P_y x_0 over P_y - m (P_x - x_0)} right] + b.

Now, knowing both Q and R, the slope of line n is

{y_1 - Q_y over x_1 - Q_x} .

We want to find the intersection of line n and the x-axis, so let

(Q_x, Q_y) + lambda (x_1 - Q_x, y_1 - Q_y) = (x,0) qquad qquad (3)

The value of λ must be adjusted so that both sides of vector equation (3) are equal. Equation (3) is actually two equations, one for abscissas and one for ordinates. The one for ordinates is

Qy + λ(y1Qy) = 0

Solve for lambda,

lambda = {-Q_y over y_1 - Q_y} qquad qquad (4)

The equation for abscissas is

x = Qx + λ(x1Qx)

which together with equation (4) yields

x = Q_x - Q_y left( {x_1 - Q_x over y_1 - Q_y} right) qquad qquad (5)

which is the abscissa of T.


Substitute the values of x1 and y1 into equation (5),

x = Q_x - Q_y left[ { {b (P_x - x_0) + P_y x_0 over P_y - m (P_x - x_0)} - Q_x over {m b (P_x - x_0) + m P_y x_0 over P_y - m (P_x - x_0)} + b - Q_y} right].

Dissolve the fractions in both numerator and denominator:

x = Q_x - Q_y left[ {b (P_x - x_0) + P_y x_0 - Q_x P_y + m Q_x (P_x - x_0) over m b (P_x - x_0) + m P_y x_0 + b P_y - m b (P_x - x_0) - Q_y P_y + m Q_y (P_x - x_0) } right].

Simplify and relabel x as t(x):

t(x) = Q_x - Q_y left[ { (P_x - x_0) (b + m Q_x) + P_y (x_0 - Q_x) over (P_x - x_0) m Q_y + P_y (m x_0 + b - Q_y) } right].

t(x) is the projective transformation.


Transformation t(x) can be simplified further. First, add its two terms to form a fraction:

t(x) = { (m Q_x P_y - Q_y P_y + b Q_y) x + (b Q_x P_y - b Q_y P_x) over m (P_y - Q_y) x + (m P_x Q_y + P_y (b - Q_y)) } qquad qquad (6)

Then, define the coefficients α, β, γ and δ to be the following

α = mQxPyQyPy + bQy,
β = bQxPybQyPx,
γ = m(PyQy),
δ = mPxQy + Py(bQy).

Substitute these coefficients into equation (6), in order to produce

t(x) = { alpha x + beta over gamma x + delta }

This is the Möbius transformation or bilinear transformation (so called because it has a linear numerator and a linear denominator. Actually, it is bilinear because the composition of projections is a binary linear operator, similar to matrix multiplication). In mathematics, a Möbius transformation is a bijective conformal mapping of the extended complex plane (i. ... In mathematics, a bilinear operator is a generalized multiplication which satisfies the distributive law. ...


Inverse transformation

It is clear from the synthetic definition that the inverse transformation is obtained by exchanging points P and Q. This can also be shown analytically. If PQ, then αα′, ββ′, γγ′, and δδ′, where

α' = mPxQyPyQy + bPy = δ,
β' = bPxQybPyQx = − β,
γ' = m(QyPy) = − γ,
δ' = mQxPy + bQyQyPy = α.

Therefore if the forwards transformation is

t(x) = {alpha x + beta over gamma x + delta}

then the transformation t′ obtained by exchanging P and Q (PQ) is:

t'(x) = {delta x - beta over - gamma x + alpha }.

Then

t'(t(x)) = {delta left( {alpha x + beta over gamma x + delta} right) - beta over - gamma left( {alpha x + beta over gamma x + delta} right) + alpha}.

Dissolve the fractions in both numerator and denominator of the right side of this last equation:

t'(t(x)) = {alpha delta x + beta delta - beta gamma x - beta delta over - alpha gamma x - beta gamma + alpha gamma x + alpha delta}
= {alpha delta x - beta gamma x over alpha delta - beta gamma} = x.

Therefore t′(x) = t−1(x): the inverse projective transformation is obtained by exchanging observers P and Q, or by letting α ↔ δ, β → −β, and γ → −γ. This is, by the way, analogous to the procedure for obtaining the inverse of a two-dimensional matrix:

begin{bmatrix} alpha & beta  gamma & delta end{bmatrix} begin{bmatrix} delta & - beta  - gamma & alpha end{bmatrix} = Delta begin{bmatrix} 1 & 0  0 & 1 end{bmatrix}

where Δ = α δ − β γ is the determinant.


Identity transformation

Also analogous with matrices is the identity transformation, which is obtained by letting α = 1, β = 0, γ = 0, and δ = 1, so that

tI(x) = x.

Composition of transformations

It remains to show that there is closure in the composition of transformations. One transformation operating on another transformation produces a third transformation. Let the first transformation be t1 and the second one be t2:

t_1(x) = {alpha_1 x + beta_1 over gamma_1 x + delta_1 },
t_2(x) = {alpha_2 x + beta_2 over gamma_2 x + delta_2 }.

The composition of these two transformations is

t_2(t_1(x)) = {alpha_2 left( {alpha_1 x + beta_1 over gamma_1 x + delta_1} right) + beta_2 over gamma_2 left( {alpha_1 x + beta_1 over gamma_1 x + delta_1 } right) + delta_2 }
= {alpha_2 alpha_1 x + alpha_2 beta_1 + beta_2 gamma_1 x + beta_2 delta_1 over gamma_2 alpha_1 x + gamma_2 beta_1 + delta_2 gamma_1 x + delta_2 delta_1 }
= {(alpha_2 alpha_1 + beta_2 gamma_1) x + (alpha_2 beta_1 + beta_2 delta_1) over (gamma_2 alpha_1 + delta_2 gamma_1) x + (gamma_2 beta_1 + delta_2 delta_1)}.

Define the coefficients α3, β3, γ3 and δ3 to be equal to

α3 = α2α1 + β2γ1,
β3 = α2β1 + β2δ1,
γ3 = γ2α1 + δ2γ1,
δ3 = γ2β1 + δ2δ1.

Substitute these coefficients into t2(t1(x)) to obtain

t_2(t_1(x)) = { alpha_3 x + beta_3 over gamma_3 x + delta_3}.

Projections operate in a way analogous to matrices. In fact, the composition of transformations can be obtained by multiplying matrices:

begin{bmatrix} alpha_2 & beta_2  gamma_2 & delta_2 end{bmatrix} begin{bmatrix} alpha_1 & beta_1  gamma_1 & delta_1 end{bmatrix} = begin{bmatrix} alpha_2 alpha_1 + beta_2 gamma_1 & alpha_2 beta_1 + beta_2 delta_1  gamma_2 alpha_1 + delta_2 gamma_1 & gamma_2 beta_1 + delta_2 delta_1 end{bmatrix} = begin{bmatrix} alpha_3 & beta_3  gamma_3 & delta_3 end{bmatrix}.

Since matrices multiply associatively, it follows that composition of projections is also associative.


Projections have: an operation (composition), associativity, an identity, an inverse and closure, so they form a group. This picture illustrates how the hours in a clock form a group. ...


The cross-ratio defined by means of a projection

Let there be a transformation ts such that ts(A) = infty, ts(B) = 0, ts(C) = 1. Then the value of ts(D) is called the cross-ratio of points A, B, C and D, and is denoted as [A, B, C, D]s:

[A,B,C,D]s = ts(D).

Let

t_s(x) = {alpha x + beta over gamma x + delta},

then the three conditions for ts(x) are met when

t_s(A) = {alpha A + beta over gamma A + delta} = infty, qquad qquad (7)
t_s(B) = {alpha B + beta over gamma B + delta} = 0, qquad qquad (8)
t_s(C) = {alpha C + beta over gamma C + delta} = 1. qquad qquad (9)

Equation (7) implies that γA + δ = 0, therefore δ = − γA. Equation (8) implies that αB + β = 0, so that β = − αB. Equation (9) becomes

{alpha C - alpha B over gamma C - gamma A} = 1,

which implies

gamma = alpha {C - B over C - A}.

Therefore

t_s(D) = {alpha D - alpha B over alpha left( {C - B over C - A} right) D - gamma A} = {alpha (D - B) over alpha left( {C - B over C - A} right) D - alpha left( {C - B over C - A} right) A}
= {D - B over C - B} {C - A over D - A} = {A - C over A - D} {B - D over B - C}. qquad qquad (10)

In equation (10), it is seen that ts(D) does not depend on the coefficients of the projection ts. It only depends on the positions of the points on the "subjective" projective line. This means that the cross-ratio depends only on the relative distances among four collinear points, and not on the projective transformation which was used to obtain (or define) the cross-ratio. The cross ratio is therefore A line, or straight line, can be described as an (infinitely) thin, (infinitely) long, perfectly straight curve (the term curve in mathematics includes straight curves). In Euclidean geometry, exactly one line can be found that passes through any two points. ...

[A,B,C,D] = {A - C over A - D} {B - D over B - C}. qquad qquad (11)

Conservation of cross-ratio

Transformations on the projective line preserve cross ratio. This will now be proven. Let there be four (collinear) points A, B, C, D. Their cross-ratio is given by equation (11). Let S(x) be a projective transformation:

S(x) = {alpha x + beta over gamma x + delta}

where alpha delta ne beta gamma. Then

[S(A) S(B) S(C) S(D)] = {{alpha A + beta over gamma A + delta} - {alpha C + beta over gamma C + delta} over {alpha A + beta over gamma A + delta} - {alpha D + beta over gamma D + delta}} cdot {{alpha B + beta over gamma B + delta} - {alpha D + beta over gamma D + delta} over {alpha B + beta over gamma B + delta} - {alpha C + beta over gamma C + delta}}
= { [(alpha A + beta) (gamma C + delta) - (alpha C + beta) (gamma A + delta)] [(alpha B + beta) (gamma D + delta) - (alpha D + beta) (gamma B + delta)] over [(alpha A + beta) (gamma D + delta) - (alpha D + beta) (gamma A + delta)] [(alpha B + beta) (gamma C + delta) - (alpha C + beta) (gamma B + delta)] }
= { [alpha A delta + beta gamma C - alpha C delta - beta gamma A] [alpha B delta + beta gamma D - alpha D delta - beta gamma B] over [alpha A delta + beta gamma D - alpha D delta - beta gamma A] [alpha B delta + beta gamma C - alpha C delta - beta gamma B]}
= { [alpha delta (A - C) + beta gamma (C - A)] [alpha delta (B - D) + beta gamma (D - B)] over [alpha delta (A - D) + beta gamma (D - A)] [alpha delta (B - C) + beta gamma (C - B)]}
= {(alpha delta - beta gamma) (A - C) (alpha delta - beta gamma) (B - D) over (alpha delta - beta gamma) (A - D) (alpha delta - beta gamma) (B - C)}
= {A - C over A - D} cdot {B - D over B - C}

Therefore [S(A) S(B) S(C) S(D)] = [A B C D], Q.E.D. Q.E.D. is an abbreviation of the Latin phrase (literally, which was to be demonstrated). In simple terms, the use of this Latin phrase is to indicate that something has been definitively proven. ...


Transformations on the projective plane

Two-dimensional projective transformations are a type of automorphism of the projective plane onto itself. In mathematics, an automorphism is an isomorphism from a mathematical object to itself. ...


Planar transformations can be defined synthetically as follows: point X on a "subjective" plane must be transformed to a point T also on the subjective plane. The transformations uses these tools: a pair of "observation points" P and Q, and an "objective" plane. The subjective and objective planes and the two points all lie in three-dimensional space, and the two planes can intersect at some line.


Draw line l1 through points P and X. Line l1 intersects the objective plane at point R. Draw line l2 through points Q and R. Line l2 intersects the projective plane at point T. Then T is the projective transform of X.


Analysis

Let the xy-plane be the "subjective" plane and let plane m be the "objective" plane. Let plane m be described by

z = f(x,y) = mx + ny + b

where the constants m and n are partial slopes and b is the z-intercept.


Let there be a pair of "observation" points P and Q,

P:(Px,Py,Pz),
Q:(Qx,Qy,Qz).

Let point X lie on the "subjective" plane:

X:(x,y,0).

Point X must be transformed to a point T,

T:(Tx,Ty,0)

also on the "subjective" plane.


The analytical results are a pair of equations, one for abscissa Tx and one for ordinate Ty: Abscissa means the x coordinate on an (x, y) graph; the input of a mathematical function against which the output is plotted. ... Ordinate means the y coordinate on an (x, y) graph; the plotted output of a mathematical function. ...

T_x = {x (-m Q_x P_z - n Q_z P_y + Q_z (P_z - b)) + (n y + b) (Q_z P_x - Q_x P_z) over (m x + n y) (Q_z - P_z) - (m P_x + n P_y) Q_z + (Q_z - b) P_z}, qquad qquad (12)
T_y = {y (-n Q_y P_z - m Q_z P_x + Q_z (P_z - b)) + (m x + b) (Q_z P_y - Q_y P_z) over (n y + m x) (Q_z - P_z) - (n P_y + m P_x) Q_z + (Q_z - b) P_z }. qquad qquad (13)

There are (at most) nine degrees of freedom for defining a 2D transformation: Px, Py, Pz, Qx, Qy, Qz, m, n, b. Notice that equations (12) and (13) have the same denominators, and that Ty can be obtained from Tx by exchanging m with n, and x with y (including subscripts of P and Q).


Trilinear transformations

Let

α = − mQxPznQzPy + Qz(Pzb),
β = n(QzPxQxPz),
γ = b(QzPxQxPz),
δ = m(QzPz),
ε = n(QzPz),
ζ = − (mPx + nPy)Qz + (Qzb)Pz,

so that

T_x = {alpha x + beta y + gamma over delta x + epsilon y + zeta}. qquad qquad (14)

Also let

η = m(QzPyQyPz),
θ = − mQzPxnQyPz + Qz(Pzb),
κ = b(QzPyQyPz),

so that

T_y = {eta x + theta y + kappa over delta x + epsilon y + zeta}. qquad qquad (15)

Equations (14) and (15) together describe the trilinear transformation.


Composition of trilinear transformations

If a transformation is given by equations (14) and (15), then such transformation is characterized by nine coefficients which can be arranged into a coefficient matrix

M_T = begin{bmatrix} alpha & beta & gamma  eta & theta & kappa  delta & epsilon & zeta end{bmatrix}.

If there are a pair T1 and T2 of planar transformations whose coefficient matrices are and , then the composition of these transformations is another planar transformation T3,

T_3 = T_2 circ T_1 ,

such that

T3(x,y) = T2(T1(x,y)).

The coefficient matrix of T3 can be obtained by multiplying the coefficient matrices of T2 and T1:

M_{T_3} = M_{T_2} , M_{T_1}.

Proof

Given T1 defined by

T_{1x} = {alpha_1 x + beta_1 y + gamma_1 over delta_1 x + epsilon_1 y + zeta_1},
T_{1y} = {eta_1 x + theta_1 y + kappa_1 over delta_1 x + epsilon_1 y + zeta_1},

and given T2 defined by

T_{2x} = {alpha_2 x + beta_2 y + gamma_2 over delta_2 x + epsilon_2 y + zeta_2},
T_{2y} = {eta_2 x + theta_2 y + kappa_2 over delta_2 x + epsilon_2 y + zeta_2},

then T3 can be calculated by substituting T1 into T2,

T_{3x} = T_{2x} ( T_{1x}, T_{1y} ) = { alpha_2 left( {alpha_1 x + beta_1 y + gamma_1 over delta_1 x + epsilon_1 y + zeta_1} right) + beta_2 left( {eta_1 x + theta_1 y + kappa_1 over delta_1 x + epsilon_1 y + zeta_1} right) + gamma_2 over delta_2 left( {alpha_1 x + beta_1 y + gamma_1 over delta_1 x + epsilon_1 y + zeta_1} right) + epsilon_2 left( {eta_1 x + theta_1 y + kappa_1 over delta_1 x + epsilon_1 y + zeta_1} right) + zeta_2}.

Multiply numerator and denominator by the same trinomial,

T_{3x} = {alpha_2 (alpha_1 x + beta_1 y + gamma_1) + beta_2 (eta_1 x + theta_1 y + kappa_1) + gamma_2 (delta_1 x + epsilon_1 y + zeta_1) over delta_2 (alpha_1 x + beta_1 y + gamma_1) + epsilon_2 (eta_1 x + theta_1 y + kappa_1) + zeta_2 (delta_1 x + epsilon_1 y + zeta_1)}.

Group the coefficients of x, y, and 1:

T_{3x} = { x (alpha_2 alpha_1 + beta_2 eta_1 + gamma_2 delta_1) + y (alpha_2 beta_1 + beta_2 theta_1 + gamma_2 epsilon_1) + (alpha_2 gamma_1 + beta_2 kappa_1 + gamma_2 zeta_1) over x (delta_2 alpha_1 + epsilon_2 eta_1 + zeta_2 delta_1) + y (delta_2 beta_1 + epsilon_2 theta_1 + zeta_2 epsilon_1) + (delta_2 gamma_1 + epsilon_2 kappa_1 + zeta_2 zeta_1)} = {alpha_3 x + beta_3 y + gamma_3 over delta_3 x + epsilon_3 y + zeta_3}.

These six coefficients of T3 are the same as those obtained through the product

begin{bmatrix} alpha_2 & beta_2 & gamma_2  eta_2 & theta_2 & kappa_2  delta_2 & epsilon_2 & zeta_2 end{bmatrix} begin{bmatrix} alpha_1 & beta_1 & gamma_1  eta_1 & theta_1 & kappa_1  delta_1 & epsilon_1 & zeta_1 end{bmatrix} = begin{bmatrix} alpha_3 & beta_3 & gamma_3  eta_3 & theta_3 & kappa_3  delta_3 & epsilon_3 & zeta_3 end{bmatrix}. qquad qquad (16)

The remaining three coefficients can be verified thus

T_{3y} = T_{2y} ( T_{1x}, T_{1y} ) = { eta_2 left( {alpha_1 x + beta_1 y + gamma_1 over delta_1 x + epsilon_1 y + zeta_1} right) + theta_2 left( {eta_1 x + theta_1 y + kappa_1 over delta_1 x + epsilon_1 y + zeta_1} right) + kappa_2 over delta_2 left( {alpha_1 x + beta_1 y + gamma_1 over delta_1 x + epsilon_1 y + zeta_1} right) + epsilon_2 left( {eta_1 x + theta_1 y + kappa_1 over delta_1 x + epsilon_1 y + zeta_1} right) + zeta_2}.

Multiply numerator and denominator by the same trinomial,

T_{3y} = {eta_2 (alpha_1 x + beta_1 y + gamma_1) + theta_2 (eta_1 x + theta_1 y + kappa_1) + kappa_2 (delta_1 x + epsilon_1 y + zeta_1) over delta_2 (alpha_1 x + beta_1 y + gamma_1) + epsilon_2 (eta_1 x + theta_1 y + kappa_1) + zeta_2 (delta_1 x + epsilon_1 y + zeta_1)}.

Group the coefficients of x, y, and 1:

T_{3x} = { x (eta_2 alpha_1 + theta_2 eta_1 + kappa_2 delta_1) + y (eta_2 beta_1 + theta_2 theta_1 + kappa_2 epsilon_1) + (eta_2 gamma_1 + theta_2 kappa_1 + kappa_2 zeta_1) over x (delta_2 alpha_1 + epsilon_2 eta_1 + zeta_2 delta_1) + y (delta_2 beta_1 + epsilon_2 theta_1 + zeta_2 epsilon_1) + (delta_2 gamma_1 + epsilon_2 kappa_1 + zeta_2 zeta_1)} = {eta_3 x + theta_3 y + kappa_3 over delta_3 x + epsilon_3 y + zeta_3}.

The three remaining coefficients just obtained are the same as those obtained through equation (16). Q.E.D. Q.E.D. is an abbreviation of the Latin phrase (literally, which was to be demonstrated). In simple terms, the use of this Latin phrase is to indicate that something has been definitively proven. ...


Planar transformations of lines

The trilinear transformation given be equations (14) and (15) transforms a straight line

y = mx + b

into another straight line

Ty = nTx + c

where n and c are constants and equal to

n = {m (epsilon kappa - zeta theta) + b (delta theta - epsilon eta) + (delta kappa - zeta eta) over m (epsilon gamma - zeta beta) + b (delta beta - epsilon alpha) + (delta gamma - zeta alpha)}

and

c = {m (beta kappa - gamma theta) + b (alpha theta - beta eta) + (alpha kappa - gamma eta) over m (beta zeta - gamma epsilon) + b (alpha epsilon - beta delta) + (alpha zeta - gamma delta) }.

Proof

Given y = m x + b, then plugging this into equations (14) and (15) yields

T_x = {alpha x + beta (m x + b) + gamma over delta x + epsilon (m x + b) + zeta} = {(alpha + beta m) x + (beta b + gamma) over (delta + epsilon m) x + (epsilon b + zeta)},

and

T_y = {(eta + theta m) x + (theta b + kappa) over (delta + epsilon m) x + (epsilon b + zeta) }.

If Ty = n Tx + c and n and c are constants, then

{partial T_y over partial x} = n {partial T_x over partial x}

so that

n = {partial T_y / partial x over partial T_x / partial y}.

Calculation shows that

{partial T_x over partial x} = { (epsilon b + zeta) (alpha + beta m) - (beta b + gamma) (delta + epsilon m) over [(delta + epsilon m) x + (epsilon b + zeta)]^2 }

and

{partial T_y over partial x} = { (epsilon b + zeta) (eta + theta m) - (theta b + kappa) (delta + epsilon m) over [(delta + epsilon m) x + (epsilon b + zeta)]^2 }

therefore

n = {partial T_y / partial x over partial T_x / partial y} = { (epsilon b + zeta) (eta + theta m) - (theta b + kappa) (delta + epsilon m) over (epsilon b + zeta) (alpha + beta m) - (beta b + gamma) (delta + epsilon m) } .

We should now obtain c to be

c = TynTx
= {(eta + theta m) x + (theta b + kappa) - left[ { (epsilon b + zeta) (eta + theta m) - (theta b + kappa) (delta + epsilon m) over (epsilon b + zeta) (alpha + beta m) - (beta b + gamma) (delta + epsilon m) } right] cdot [ (alpha + beta m) x + (beta b + gamma) ] over (delta + epsilon m) x + (epsilon b + zeta) }.

Add the two fractions in the numerator:

c = { left{ [(epsilon b + zeta) (alpha + beta m) - (beta b + gamma) (delta + epsilon m)] [(eta + theta m) x + (theta b + kappa)] - [(epsilon b + zeta) (eta + theta m) - (theta b + kappa) (delta + epsilon m)] [(alpha + beta m) x + (beta b + gamma)] right} over [(delta + epsilon m) x + (epsilon b + zeta)] [(epsilon b + zeta) (alpha + beta m) - (beta b + gamma) (delta + epsilon m)] }.

Distribute binomials in parentheses in the numerator, then cancel out equal and opposite terms:

c = { - (beta b + gamma) (delta + epsilon m) (eta + theta m) x + (epsilon b + zeta) (alpha + beta m) (theta b + kappa) + (theta b + kappa) (delta + epsilon m) (alpha + beta m) x - (epsilon b + zeta) (eta + theta m) (beta b + gamma) over [(delta + epsilon m) x + (epsilon b + zeta)] [(epsilon b + zeta) (alpha + beta m) - (beta b + gamma) (delta + epsilon m)] }.

Factor the numerator into a pair of terms, only one of them having the numerus cossicus (x). There is another numerus cossicus in the denominator. The objective now is to get both of these to cancel out.

c = { left{ [(theta b + kappa) (alpha + beta m) - (beta b + gamma) (eta + theta m)] (delta + epsilon m) x + [(alpha + beta m)(theta b + kappa) - (eta + theta m) (beta b + gamma)] (epsilon b + zeta) right} over [(delta + epsilon m) x + (epsilon b + zeta)] [(epsilon b + zeta) (alpha + beta m) - (beta b + gamma) (delta + epsilon m)] }.

Factor the numerator,

c = {[(theta b + kappa) (alpha + beta m) - (beta b + gamma) (eta + theta m)] [(delta + epsilon m) x + (epsilon b + zeta)] over [(epsilon b + zeta) (alpha + beta m) - (beta b + gamma) (delta + epsilon m)] [(delta + epsilon m) x + (epsilon b + zeta)] }.

The terms with the numeri cossici cancel out, therefore

c = { (alpha + beta m) (theta b + kappa) - (beta b + gamma) (eta + theta m) over (alpha + beta m) (epsilon b + zeta) - (beta b + gamma) (delta + epsilon m) }

is a constant. Q.E.D. Q.E.D. is an abbreviation of the Latin phrase (literally, which was to be demonstrated). In simple terms, the use of this Latin phrase is to indicate that something has been definitively proven. ...


Comparing c with n, notice that their denominators are the same. Also, n is obtained from c by exchanging the following coefficients:

alpha leftrightarrow delta,  beta leftrightarrow epsilon,  gamma leftrightarrow zeta .

There is also the following exchange symmetry between the numerator and denominator of n: Sphere symmetry group o. ...

alpha leftrightarrow eta,  beta leftrightarrow theta,  gamma leftrightarrow kappa .

The numerator and denominator of c also have exchange symmetry: { eta leftrightarrow delta,  theta leftrightarrow epsilon,  kappa leftrightarrow zeta }.


The exchange symmetry between n and c can be chunked into binomials: Chunking may have several meanings: In cognitive psychology and in memory training systems, chunking refers to a short-term memory mechanism and techniques to exploit it. ...

n leftrightarrow c equiv { (alpha + m beta ) leftrightarrow (delta + m epsilon ),  (gamma + b beta ) leftrightarrow (zeta + b epsilon ) }.

All of these exchange symmetries amount to exchanging pairs of rows in the coefficient matrix.


Planar transformations of conic sections

A trilinear transformation such as T given by equations (14) and (15) will convert a conic section Types of conic sections Table of conics, Cyclopaedia, 1728 In mathematics, a conic section (or just conic) is a curve formed by intersecting a cone (more precisely, a right circular conical surface) with a plane. ...

A x^2 + B y^2 + C x + D y + E x y + F = 0 qquad qquad (17)

into another conic section

A' T_x^2 + B' T_y^2 + C' T_x + D' T_y + E' T_x T_y + F' = 0. qquad qquad (18)

Proof

Let there be given a conic section described by equation (17) and a planar transformation T described by equations (15) and (16) which converts points (x,y) into points (Tx,Ty).


It is possible to find an inverse transformation T′ which converts back points (Tx,Ty) to points (x,y). This inverse transformation has a coefficient matrix

M_{T'} = begin{bmatrix} alpha' & beta' & gamma'  eta' & theta' & kappa'  delta' & epsilon' & zeta' end{bmatrix}.

Equation (17) can be expressed in terms of the inverse transformation:

A left( {alpha' T_x + beta' T_y + gamma' over delta' T_x + epsilon' T_y + zeta'} right)^2 + B left( {eta' T_x + theta' T_y + kappa' over delta' T_x + epsilon' T_y + zeta'} right)^2 + C left( {alpha' T_x + beta' T_y + gamma' over delta' T_x + epsilon' T_y + zeta'} right) + D left( {eta' T_x + theta' T_y + kappa' over delta' T_x + epsilon' T_y + zeta'} right) + E left( {alpha' T_x + beta' T_y + gamma' over delta' T_x + epsilon' T_y + zeta'} right) left( {eta' T_x + theta' T_y + kappa' over delta' T_x + epsilon' T_y + zeta'} right) + F = 0.

The denominators can be "dissolved" by multiplying both sides of the equation by the square of a trinomial:

A(α'Tx + β'Ty + γ')2 + B(η'Tx + θ'Ty + κ')2 + C(α'Tx + β'Ty + γ')(δ'Tx + ε'Ty + ζ') + D(η'Tx + θ'Ty + κ')(δ'Tx + ε'Ty + ζ') + E(α'Tx + β'Ty + γ')(η'Tx + θ'Ty + κ') + F(δ'Tx + ε'Ty + ζ')2 = 0.

Expand the products of trinomials and collect common powers of Tx and Ty:

begin{matrix} (A alpha'^2 + B eta'^2 + C alpha' delta' + D eta' delta' + E alpha' eta' + F delta'^2) T_x^2  + (A beta'^2 + B theta'^2 + C beta' epsilon' + D theta' epsilon' + E beta' theta' + F epsilon'^2) T_y^2  + (2 A alpha' gamma' + 2 B eta' kappa' + C (alpha' zeta' + gamma' delta') + D (eta' zeta' + kappa' delta') + E (alpha' kappa' + gamma' eta') + 2 F delta' zeta') T_x  + (2 A beta' gamma' + 2 B theta' kappa' + C (beta' zeta' + gamma' epsilon') + D (theta' zeta' + kappa' epsilon') + E (beta' kappa' + gamma' theta') + 2 F epsilon' zeta') T_y  + (2 A alpha' beta' + 2 B eta' theta' + C (alpha' epsilon' + beta' delta') + D (eta' epsilon' + theta' delta') + E (alpha' theta' + beta' eta') + 2 F delta' epsilon') T_x T_y  + (A gamma'^2 + B kappa'^2 + C gamma' zeta' + D kappa' zeta' + E gamma' kappa' + F zeta'^2) = 0. end{matrix} qquad qquad (19)

Equation (19) has the same form as equation (18).


What remains to do is to express the primed coefficients in terms of the unprimed coefficients. To do this, apply Cramer's rule to the coefficient matrix MT to obtain the primed matrix of the inverse transformation: Cramers rule is a theorem in linear algebra, which gives the solution of a system of linear equations in terms of determinants. ...

M_{T'} = {1 over Delta} begin{bmatrix} left| begin{matrix} theta &kappa  epsilon & zeta end{matrix} right| & left| begin{matrix} epsilon & zeta  beta & gamma end{matrix} right| & left| begin{matrix} beta & gamma  theta & kappa end{matrix} right|  quad & quad & quad  left| begin{matrix} kappa & eta  zeta & delta end{matrix} right| & left| begin{matrix} zeta & delta  gamma & alpha end{matrix} right| & left| begin{matrix} gamma & alpha  kappa & eta end{matrix} right|  quad & quad & quad  left| begin{matrix} eta & theta  delta & epsilon end{matrix} right| & left| begin{matrix} delta &epsilon  alpha & beta end{matrix} right| & left| begin{matrix} alpha & beta  eta & theta end{matrix} right| end{bmatrix} qquad qquad (20)

where Δ is the determinant of the unprimed coefficient matrix.


Equation (20) allows primed coefficients to be expressed in terms of unprimed coefficients. But performing these substitutions on the primed coefficients of equation (19) it can be noticed that the determinant Δ cancels itself out, so that it can be ignored altogether. Therefore

A' = A(θζ − κε)2 + B(κδ − ηζ)2 + C(θζ − κε)(ηε − θδ) + D(κδ − ηζ)(ηε − θδ) + E(θζ − κε)(κδ − ηζ) + F(ηε − θδ)2
B' = A(εγ − ζβ)2 + B(ζα − δγ)2 + C(εγ − ζβ)(δβ − εα) + D(ζα − δγ)(δβ − εα) + E(εγ − ζβ)(ζα − δγ) + F(δβ − εα)2
C' = 2A(θζ − κε)(βκ − γθ) + 2B(κδ − ηζ)(γη − ακ) + C[(θζ − κε)(αθ − βη) + (βκ − γθ)(ηε − θδ)] + D[(κδ − ηζ)(αθ − βη) + (γη − ακ)(ηε − θδ)] + E[(θζ − κε)(γη − ακ) + (βκ − γθ)(κδ − ηζ)] + 2F(ηε − θδ)(αθ − βη)
D' = 2A(εγ − ζβ)(βκ − γθ) + 2B(ζα − δγ)(γη − ακ) + C[(εγ − ζβ)(αθ − βη) + (βκ − γθ)(δβ − εα)] + D[(ζα − δγ)(αθ − βη) + (γη − ακ)(δβ − εα)] + E[(εγ − ζβ)(γη − ακ) + (βκ − γθ)(ζα − δγ)] + 2F(δβ − εα)(αθ − βη)
E' = 2A(θζ − κε)(εγ − ζβ) + 2B(κδ − ηζ)(ζα − δγ) + C[(θζ − κε)(δβ − εα) + (εγ − ζβ)(ηε − θδ)] + D[(κδ − ηζ)(δβ − εα) + (ζα − δγ)(ηε − θδ)] + E[(θζ − κε)(ζα − δγ) + (εγ − ζβ)(κδ − ηζ)] + 2F(ηε − θδ)(δβ − εα)
F' = A(βκ − γθ)2 + B(γη − ακ)2 + C(βκ − γθ)(αθ − βη) + D(γη − ακ)(αθ − βη) + E(βκ − γθ)(γη − ακ) + F(αθ − βη)2

The coefficients of the transformed conic have been expressed in terms of the coefficients of the original conic and the coefficients of the planar transformation T. Q.E.D. Q.E.D. is an abbreviation of the Latin phrase (literally, which was to be demonstrated). In simple terms, the use of this Latin phrase is to indicate that something has been definitively proven. ...


Planar projectivities and cross-ratio

Let four points A, B, C, D be collinear. Let there be a planar projectivity T which transforms these points into points A′, B′, C′, and D′. It was already shown that lines are transformed into lines, so that the transformed points A′ through D′ will also be collinear. Then it will turn out that the cross-ratio of the original four points is the same as the cross-ratio of their transforms:

[A  B  C  D] = [A'  B'  C'  D'].

Proof

If the two-dimensional coordinates of four points are known, and if the four points are collinear, then their cross-ratio can be found from their abscissas alone. It is possible to project the points onto a horizontal line by means of a pencil of vertical lines issuing from a point on the line at infinity: Abscissa means the x coordinate on an (x, y) graph; the input of a mathematical function against which the output is plotted. ... In geometry and topology, the line at infinity is a line which is added to the real (affine) plane in order to give closure to, and remove the exceptional cases from, the incidence properties of the resulting projective plane. ...

[A  B  C  D] = [A_x  B_x  C_x  D_x].

The same is true for the ordinates of the points. The reason is that any mere rescaling of the coordinates of the points does not change the cross-ratio. Ordinate means the y coordinate on an (x, y) graph; the plotted output of a mathematical function. ...


Let

A:(x1,mx1 + b),
B:(x2,mx2 + b),
C:(x3,mx3 + b),
D:(x4,mx4 + b).

Clearly these four points are collinear. Let

T_x (x,y) = {alpha x + beta y + gamma over delta x + epsilon y + zeta}

be the first half of a trilinear transformation. Then

T_x(A) = {alpha x_1 + beta (m x_1 + b) + gamma over delta x_1 + epsilon (m x_1 + b) + zeta} = {(alpha + beta m) x_1 + (beta b + gamma) over (delta + epsilon m) x_1 + (epsilon b + zeta)},
T_x(B) = {alpha x_2 + beta (m x_2 + b) + gamma over delta x_2 + epsilon (m x_2 + b) + zeta} = {(alpha + beta m) x_2 + (beta b + gamma) over (delta + epsilon m) x_2 + (epsilon b + zeta)},
T_x(C) = {alpha x_3 + beta (m x_3 + b) + gamma over delta x_3 + epsilon (m x_3 + b) + zeta} = {(alpha + beta m) x_3 + (beta b + gamma) over (delta + epsilon m) x_3 + (epsilon b + zeta)},
T_x(D) = {alpha x_4 + beta (m x_4 + b) + gamma over delta x_4 + epsilon (m x_4 + b) + zeta} = {(alpha + beta m) x_4 + (beta b + gamma) over (delta + epsilon m) x_4 + (epsilon b + zeta)}.

The original cross-ratio is

It is not necessary to calculate the transformed cross-ratio. Just let

be a bilinear transformation. Then S(x) is a one-dimensional projective transformation. But Tx(A)=S(A), Tx(B)=S(B), Tx(C)=S(C), and Tx(D)=S(D). Therefore

but it has already been shown that bilinear transformations preserve cross-ratio. Q.E.D. Q.E.D. is an abbreviation of the Latin phrase (literally, which was to be demonstrated). In simple terms, the use of this Latin phrase is to indicate that something has been definitively proven. ...


Example

The following is a rather simple example of a planar projectivity:

The coefficient matrix of this projectivity T is

and it is easy to verify that MT is its own inverse. Look up inverse in Wiktionary, the free dictionary. ...


The locus of points described parametrically as describe a circle, due to the trigonometric identity In mathematics, a locus (Latin for place, plural loci) is a collection of points which share a common property. ... Circle illustration This article is about the shape and mathematical concept of circle. ... In mathematics, trigonometric identities are equations involving trigonometric functions that are true for all values of the occurring variables. ...

cos2θ + sin2θ = 1

which has the same form as the canonical equation of a circle. Applying the projectivity T yields the locus of points described parametrically by which describe a hyperbola, due to the trigonometric identity A graph of a hyperbola. ...

sec2θ − tan2θ = 1

which has the same form as the canonical equation of a hyperbola. Notice that points and (1,0) are fixed points.


Indeed, this projectivity transforms any circle, of any radius, into a hyperbola centered at the origin with both of its foci lying on the x-axis, and vice versa. This projectivity also transforms the y-axis into the line at infinity, and vice versa: In geometry, the focus (pl. ... In geometry and topology, the line at infinity is a line which is added to the real (affine) plane in order to give closure to, and remove the exceptional cases from, the incidence properties of the resulting projective plane. ...

The ratio of infinity over infinity is indeterminate which means that it can be set to any value y desired. The infinity symbol ∞ in several typefaces. ...


This example emphasizes that in the real projective plane, RP2, a hyperbola is a closed curve which passes twice through the line at infinity. But what does the transformation do to a parabola? For other uses, see Parabola (disambiguation). ...


Let the locus of points (x,x2) describe a parabola. Its transformation is

which is a hyperbola whose asymptotes are the x-axis and the y-axis and whose wings lie in the first quadrant and the third quadrant. Likewise, the hyperbola An asymptote is a straight line or curve which a curve approaches as one moves along the curve. ... Look up Quadrant on Wiktionary, the free dictionary Quadrant can mean: HMS Quadrant (G11), a WW-II British/Australian warship. ...

is transformed by T into the parabola

.

On the other hand, the parabola described by the locus of points is transformed by T into itself: this demonstrates that a parabola intersects the line at infinity at a single point.


Transformations in projective 3-space

Three-dimensional transformations can be defined synthetically as follows: point X on a "subjective" 3-space must be transformed to a point T also on the subjective space. The transformations uses these elements: a pair of "observation points" P and Q, and an "objective" 3-space. The subjective and objective spaces and the two points all lie in four-dimensional space, and the two 3-spaces can intersect at some plane.


Draw line l1 through points X and P. This line intersects the objective space at point R. Draw line l2 through points R and Q. Line l2 intersects the projective plane at point T. Then T is the transform of X.


Analysis

Let

X:(x,y,z,0),
T:(Tx,Ty,Tz,0),
P:(Px,Py,Pz,Pt),
Q:(Qx,Qy,Qz,Qt).

Let there be an "objective" 3-space described by

t = f(x,y,z) = mx + ny + kz + b

Draw line l1 through points P and X. This line intersects the objective plane at R. This intersection can be described parametrically as follows:

(1 − λ1)X + λ1P = (Rx,Ry,Rz,mRx + nRy + kRz + b).

This implies the following four equations:

Rx = x + λ1(Pxx)
Ry = y + λ1(Pyy)
Rz = z + λ1(Pzz)
Rt = λ1Pt = mRx + nRy + kRz + b

Substitute the first three equations into the last one:

(mx + ny + kz) + λ1(mPx + nPy + kPzmxnykzPt) + b = 0

Solve for λ1,

Draw line l2 through points R and Q. This line intersects the subjective 3-space at T. This intersection can be represented parametrically as follows:

(1 − λ2)R + λ2Q = (Tx,Ty,Tz,0)

This implies the following four equations:

Tx = Rx + λ2(QxRx),
Ty = Ry + λ2(QyRy),
Tz = Rz + λ2(QzRz),
Rt + λ2(QtRt) = 0.

The last equation can be solved for λ2,

which can then be substituted into the other three equations:

Substitute the values for Rx, Ry, Rz, and Rt obtained from the first intersection into the above equations for Tx, Ty, and Tz,

Multiply both numerators and denominators of the above three equations by the denominator of lambda1: λ1D,

Plug in the values of the numerator and denominator of lambda1:

λ1N = b + mx + ny + kz
λ1D = Pt + m(xPx) + n(yPy) + k(zPz)

to obtain

,
TyN = (b + mx + ny + kz)[PtQyQt(Pyy)] − yQt[Pt + m(xPx) + n(yPy) + k(zPz)],
.

The numerator TxN can be expanded. It will be found that second-degree terms of x, y, and z will cancel each other out. Then collecting terms with common x, y, and z yields

TxN = x(mPtQx + nPyQt + kPzQt + Qt(bPt)) + yn(PtQxPxQt) + zk(PtQxPxQt) + b(PtQxPxQt)

Likewise, the denominator becomes

TxD = (mx + ny + kz)(PtQt) + (mPx + nPy + kPz)Qt + Pt(bQt).

The numerator TyN, when expanded and then simplified, becomes

TyN = xm(PtQyPyQt) + y(mPxQt + nPtQy + kPzQt + Qt(bPt)) + zk(PtQyPyQt) + b(PtQyPyQt).

Likewise, the numerator TzN becomes

TzN = xm(PtQzPzQt) + yn(PtQzPzQt) + z(mPxQt + nPyQt + kPtQz + Qt(bPt)) + b(PtQzPzQt).

Quadrilinear transformations

Let

α = mPtQx + nPyQt + kPzQt + Qt(bPt),
β = n(PtQxPxQt),
γ = k(PtQxPxQt),
δ = b(PtQxPxQt),
ε = m(PtQt),
ζ = n(PtQt),
η = k(PtQt),
θ = (mPx + nPy + kPz)Qt + Pt(bQt),
ι = m(PtQyPyQt),
κ = mPxQt + nPtQy + kPzQt + Qt(bPt),
λ = k(PtQyPyQt),
μ = b(PtQyPyQt),
ν = m(PtQzPzQt),
ξ = n(PtQzPzQt),
o = mPxQt + nPyQt + kPtQz + Qt(bPt),
ρ = b(PtQzPzQt).

Then the transformation in 3-space can be expressed as follows,

The sixteen coefficients of this transformation can be arranged in a coefficient matrix

Whenever this matrix is invertible, its coefficients will describe a quadrilinear transformation.


Transformation T in 3-space can also be represented in terms of homogeneous coordinates as In mathematics, homogeneous coordinates, introduced by August Ferdinand Möbius, allow affine transformations to be easily represented by a matrix. ...

This means that the coefficient matrix of T can operate directly on 4-component vectors of homogeneous coordinates. Transformation of a point can be effected simply by multiplying the coefficient matrix with the position vector of the point in homogeneous coordinates. Therefore, if T transforms a point on the plane at infinity, the result will be In projective geometry, the plane at infinity is a projective plane which is added to the affine 3-space in order to give it closure of incidence properties. ...

If ε, ζ, and η are not all equal to zero, then T will transform the plane at infinity into a locus of points which lie mostly in affine space. If ε, ζ, and η are all zero, then T will be a special kind of projective transformation called an affine transformation, which transforms affine points into affine points and ideal points (i.e. points at infinity) into ideal points.


The group of affine transformations has a subgroup of affine rotations whose matrices have the form In linear algebra and geometry, a coordinate rotation is a type of transformation from one system of coordinates to another system of coordinates such that distance between any two points remains invariant under the transformation. ...

such that the submatrix

is orthogonal. In matrix theory, a real orthogonal matrix is a square matrix Q whose transpose is its inverse: // Overview An orthogonal matrix is the real specialization of a unitary matrix, and thus always a normal matrix. ...


Properties of quadrilinear transformations

Given a pair of quadrilinear transformations T1 and T2, whose coefficient matrices are and , then the composition of these pair of transformations is another quadrilinear transformation T3 whose coefficient matrix is equal to the product of the first and second coefficient matrices,

The identity quadrilinear transformation TI is the transformation whose coefficient matrix is the identity matrix. In linear algebra, the identity matrix of size n is the n-by-n square matrix with ones on the main diagonal and zeros elsewhere. ...


Given a spatial projectivity T1 whose coefficient matrix is , the inverse of this projectivity is another projectivity T−1 whose coefficient matrix is the inverse of T1′s coefficient matrix,

.

Composition of quadrilinear transformations is associative, therefore the set of all quadrilinear transformations, together with the operation of composition, form a group. This picture illustrates how the hours in a clock form a group. ...


This group of quadrilinear transformations contains subgroups of trilinear transformations. For example, the subgroup of all quadrilinear transformations whose coefficient matrices have the form

is isomorphic to the group of all trilinear transformations whose coefficient matrices are

This subgroup of quadrilinear transformations all have the form

This means that this subgroup of transformations will act on the plane z = 0 just like a group of trilinear transformations.


Spatial transformations of planes

Projective transformations in 3-space transform planes into planes. This can be demonstrated more easily using homogeneous coordinates.


Let

z = mx + ny + b

be the equation of a plane. This is equivalent to

Equation (21) can be expressed as a matrix product:

A permutation matrix can be interposed between the two vectors, in order to make the plane vector have homogeneous coordinates: Permutation is the arrangement of symbols or objects into distinguishable orderings. ...

A quadrilinear transformation should convert this to

where

Equation (22) is equivalent to where

etc.

Applying equation (24) to equation (25) yields

Combining equations (26) and (23) produces

Solve for [Tm:Tn:Tb:1]T,

Equation (27) describes how 3-space transformations convert a plane (m, n, b) into another plane (Tm, Tn, Tb) where

See also

In mathematics, the fundamental theorem of projective geometry states that if Pn is a projective space and F and F′ are frames of Pn, then there exists a unique projective transformation sending F to F′. In case n = 1 this comes down to saying that given two ordered...

Reference


  Results from FactBites:
 
Projective transformation - Wikipedia, the free encyclopedia (2853 words)
A projective transformation is a transformation used in projective geometry: it is the composition of a pair of perspective projections.
Projective transformations do not preserve sizes or angles but do preserve incidence and cross-ratio: two properties which are important in projective geometry.
Composition of quadrilinear transformations is associative, therefore the set of all quadrilinear transformations, together with the operation of composition, form a group.
Projective geometry - Wikipedia, the free encyclopedia (1199 words)
Projective geometry is a non-metrical form of geometry that emerged in the early 19th century.
Projective geometry can be formulated as an axiomatic first order theory (with identity), whose universe contains "points" and "lines." Hence there are two primitive sets, one whose members are the points and the other whose members are the lines.
Projective geometry also includes a full theory of conic sections, a subject already very well developed in Euclidian geometry (and mainly useful as a source of examination questions).
  More results at FactBites »


 

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