FACTOID # 151: The five countries with the highest coffee consumption are also the five countries whose citizens trust one another the most. Coincidence? Probably.
 
 Home   Encyclopedia   Statistics   Countries A-Z   Flags   Maps   Education   Forum   FAQ   About 
 
WHAT'S NEW
RECENT ARTICLES
More Recent Articles »
 

SEARCH ALL

FACTS & STATISTICS    Advanced view

Search encyclopedia, statistics and forums:

 

 

(* = Graphable)

 

 


Encyclopedia > Tsiolkovsky rocket equation

Tsiolkovsky's rocket equation, named after Konstantin Tsiolkovsky who independently derived it, considers the principle of a rocket: a device that can apply an acceleration to itself (a thrust) by expelling part of its mass with high speed in the opposite direction, due to the conservation of momentum. Konstantin Eduardovich Tsiolkovsky Konstantin Eduardovich Tsiolkovsky (Konstanty Ciołkowski), (Константин Эдуардович Циолковский; September 5, 1857 new style – September 19, 1935) was a Russian and Soviet rocket scientist and pioneer of cosmonautics who spent most of his life in a log-house at the outskirts of the Russian town of Kaluga. ... A Redstone rocket, part of the Mercury program A rocket is a vehicle, missile or aircraft which obtains thrust by the reaction to the ejection of fast moving exhaust gas from within a rocket engine. ... Thrust is a reaction force described quantitatively by Newtons Second and Third Law. ... In classical mechanics momentum (pl. ...


It says that for any maneuver or any journey involving a number of maneuvers:

Delta v = v_e ln frac {m_0} {m_1}

or equivalently

m_1=m_0 e^{-Delta v / v_e}      or      m_0=m_1 e^{Delta v / v_e}

where m0 is the initial total mass, and m1 the final total mass and ve the velocity of the rocket exhaust with respect to the rocket (the specific impulse, or, if measured in time, that multiplied by gravity-on-Earth acceleration). The specific impulse (commonly abbreviated Isp) of a propulsion system is the impulse (change in momentum) per unit of propellant. ... Gravity is a force of attraction that acts between bodies that have mass. ...

1-frac {m_1} {m_0}=1-e^{-Delta v / v_e}is the mass fraction (the part of the initial total mass that is spent as reaction mass).

Δv (delta v) is the integration over time of the magnitude of the acceleration produced by using the rocket engine (what would be the actual acceleration if external forces were absent). In free space, for the case of acceleration in the direction of the velocity, this is the increase of the speed. In the case of an acceleration in opposite direction (deceleration) it is the decrease of the speed. In aerospace engineering, the mass fraction is an important measure of a rockets efficiency. ... In general physics, delta-v is simply the change in velocity. ...


Of course gravity and drag also accelerate the vehicle, and they can add or subtract to the change in velocity experienced by the vehicle. Hence delta-v is not usually the actual change in speed or velocity of the vehicle.


The equation is obtained by integrating the conservation of momentum equation In calculus, the integral of a function is a generalization of area, mass, volume and total. ... In physics, a conservation law states that a particular measurable property of an isolated physical system does not change as the system evolves. ...

mdv = vedm

for a simple rocket that emits mass at a constant velocity (dm is here the reaction mass; if it is the change of the rocket mass then there is a minus sign in the latter equation).


Although an extreme simplification, the rocket equation captures the essentials of rocket flight physics in a single short equation. It also happens that delta-v is one of the most important quantities in orbital mechanics, that quantifies how difficult it is to perform a given orbital maneuver. An orbital maneuver is a change from one orbit to another, accomplished by applying thrust. ...


Clearly, to achieve a large delta-v, either m0 must be huge (growing exponentially as delta-v rises), or m1 must be tiny, or ve must be very high, or some combination of all of these. In mathematics, a quantity that grows exponentially (or geometrically) is one that grows at a rate proportional to its size. ...


In practice, this has been achieved by using very large rockets (increasing m0), with multiple stages (decreasing m1), and rockets with very high exhaust velocities. The Saturn V rockets used in the Apollo space program and the ion thrusters used in long-distance unmanned probes are good examples of this. This article is about the rocket. ... Apollo Program insignia Apollo CSM in lunar orbit. ... This article or section does not cite its references or sources. ...


The rocket equation shows a kind of "exponential decay" of mass, not as a function of time, but as a function of delta-v produced. The delta-v that is the corresponding "half-life" is v_e ln 2 approx 0.693 v_e It has been suggested that half-life be merged into this article or section. ... Half-Life For a quantity subject to exponential decay, the half-life is the time required for the quantity to fall to half of its initial value. ...

Contents


History

This equation was independently derived by Konstantin Tsiolkovsky towards the end of the 19th century and is widely known under this name. However a recently discovered pamphlet "A Treatise on the Motion of Rockets" by William Moore [1] shows that the earliest known derivation of this kind of equation was in fact in Royal Military Academy at Woolwich in England in 1813, and was used for weapons research. Konstantin Eduardovich Tsiolkovsky Konstantin Eduardovich Tsiolkovsky (Konstanty Ciołkowski), (Константин Эдуардович Циолковский; September 5, 1857 new style – September 19, 1935) was a Russian and Soviet rocket scientist and pioneer of cosmonautics who spent most of his life in a log-house at the outskirts of the Russian town of Kaluga. ... William Moore (fl. ... The Royal Military Academy was founded in 1741 in Woolwich, south-east London. ... Woolwich is a town in south-east London, England in the London Borough of Greenwich, on the south side of the River Thames, though the tiny exclave of North Woolwich (which is now part of the London Borough of Newham) is on the north side of the river. ...


Stages

In the case of subsequently thrusting rocket stages, the equation applies for each stage, where for each stage the initial mass in the equation is the total mass of the rocket after discarding the previous stage, and the final mass in the equation is the total mass of the rocket just before discarding the stage concerned. For each stage the specific impulse may be different. The second stage of a Minuteman III rocket Description A multistage (or multi-stage) rocket is, like any rocket, propelled by the recoil pressure of the burning gases it emits as it burns fuel. ...


For example, if 80% of the mass of a rocket is the fuel of the first stage, and 10% is the dry mass of the first stage, and 10 % is the remaining rocket, then

Δv = veln5 = 1.61ve

With three similar, subsequently smaller stages we have

Δv = 3veln5 = 4.83ve

and the payload is 0.1% of the initial mass.


A comparable SSTO rocket, also with a 0.1 % payload, could have a mass of 11% for fuel tanks and engines, and 88.9% for fuel. This would give A single-stage to orbit (or SSTO) launcher describes an as-yet theoretical class of spacecraft designed to place a load into orbit as a self-contained vehicle without the use of multiple stages. ...

Δv = veln(100 / 11.1) = 2.20ve

If the engine of a new stage is ignited before the previous stage has been discarded and the simultaneously working engines have a different specific impulse (as is often the case with solid rocket boosters and a liquid-fuel stage), the situation is more complicated.


Energy

In the ideal case m1 is useful payload and m0m1 is reaction mass (this corresponds to empty tanks having no mass, etc.). The energy required can simply be computed as

frac{1}{2}(m_0-m_1)v_e^2

Seemingly this is just the kinetic energy of the reaction mass and not the kinetic energy required for the payload, but if e.g ve=10 km/s and the speed of the rocket is 3 km/s, then the speed of the reaction mass changes only from 3 to 7 km/s; the energy thus "saved" corresponds to the increase of the specific kinetic energy (kinetic energy per kg) for the rocket. In general: Specific kinetic energy is kinetic energy per unit mass (J/kg). ...


dleft(frac{1}{2}v^2right)=vdv=vv_edm/m=frac{1}{2}left(v_e^2-(v-v_e)^2+v^2right)dm/m


Thus the specific energy gain of the rocket in any small time interval is the energy gain of the rocket including the remaining fuel, divided by its mass, where the energy gain is equal to the energy produced by the fuel minus the energy gain of the reaction mass. The larger the speed of the rocket, the smaller the energy gain of the reaction mass; if the rocket speed is more than half of the exhaust speed the reaction mass even loses energy on being expelled, to the benefit of the energy gain of the rocket; the larger the speed of the rocket, the larger the energy loss of the reaction mass.


We have

Delta epsilon = int v, d (Delta v)

where ε is the specific energy of the rocket (potential plus kinetic energy) and Δv is a separate variable, not just the change in v. In the case of using the rocket for deceleration, i.e. expelling reaction mass in the direction of the velocity, v should be taken negative.


The formula is for the ideal case again, with no energy lost on heat, etc. The latter causes a reduction of thrust, so it is a disadvantage even when the objective is to lose energy (deceleration).


If the energy is produced by the mass itself, as in a chemical rocket, the fuel value has to be :frac{1}{2}v_e^2, where for the fuel value also the mass of the oxidizer has to be taken into account. A typical value is ve = 4.5 km/s, corresponding to a fuel value of 10.1 MJ/kg. The actual fuel value is higher, but part of the energy is lost on heat that flows off as radiation. The fuel value or relative energy density is the quantity of potential energy in fuel, food or other substance. ...


The required energy is

E = frac{1}{2}m_1left(e^{Delta v / v_e}-1right)v_e^2

Conclusions:

  • for Delta v ll v_e we have Eapprox frac{1}{2}m_1 v_e Delta v
  • for a given Δv, the minimum energy is needed if ve = 0.6275Δv, requiring an energy of
E = 0.772m1v)2.
Starting from zero speed this is 54.4 % more than just the kinetic energy of the payload. Starting from a nonzero speed the required energy may be less than the increase in energy in the payload. This can be the case when the reaction mass has a lower speed after being expelled than before. For example, from a LEO of 300 km altitude to an escape orbit is an increase of 29.8 MJ/kg, which, using a specific impulse of 4.5 km/s, has a net cost of 20.6 MJ/kg (Δv = 3.20 km/s; the energies are per kg payload).

This optimization does not take into account the masses of various kinds of engines.


Also, for a given objective such as moving from one orbit to another, the required Δv may depend greatly on the rate at which the engine can produce Δv and maneuvers may even be impossible if that rate is too low. For example, a launch to LEO normally requires a Δv of ca. 9.5 km/s (mostly for the speed to be acquired), but if the engine could produce Δv at a rate of only slightly more than g, it would be a slow launch requiring altogether a very large Δv (think of hovering without making any progress in speed or altitude, it would cost a Δv of 9.8 m/s each second). If the possible rate is only g or less, the maneuver can not be carried out at all with this engine. A low Earth orbit (LEO) is an orbit in which objects such as satellites are below intermediate circular orbit (ICO) and far below geostationary orbit, but typically around 350 - 1400 km above the Earths surface. ... The acceleration due to gravity denoted g (also gee, g-force or g-load) is a non-SI unit of acceleration defined as exactly 9. ...


The power is given by In physics, power (symbol: P) is the amount of work done per unit of time. ...

P= frac{1}{2} m a v_e = frac{1}{2}F v_e

where F is the thrust and a the acceleration due to it. Thus the theoretically possible thrust per unit power is 2 divided by the specific impulse in m/s. The thrust efficiency is the actual thrust as percentage of this.


If e.g. solar power is used this restricts a; in the case of a large ve the possible acceleration is inversely proportional to it, hence the time to reach a required delta-v is proportional to ve; with 100% efficiency: Solar power describes a number of methods of harnessing energy from the light of the sun. ...

  • for Delta v ll v_e we have tapprox frac{m v_e Delta v}{2P}

Examples:

  • power 1000 W, mass 100 kg, Δv= 5 km/s, ve= 16 km/s, takes 1.5 months.
  • power 1000 W, mass 100 kg, Δv= 5 km/s, ve= 50 km/s, takes 5 months.

Thus ve should not be too large.


Examples

Assume an exhaust velocity of 4.5 km/s and a Δv of 9.7 km/s (Earth to LEO).

  • SSTO rocket: 1 − e − 9.7 / 4.5 = 0.884, therefore 88.4 % of the initial total mass has to be propellant. The remaining 11.6 % is for the engines, the tank, and the payload. In the case of a space shuttle, it would also include the orbiter.
  • Two stage to orbit: suppose that the first stage should provide a Δv of 5.0 km/s; 1 − e − 5.0 / 4.5 = 0.671, therefore 67.1% of the initial total mass has to be propellant. The remaining mass is 32.9 %. After deposing of the first stage, a mass remains equal to this 32.9 %, minus the mass of the tank and engines of the first stage. Assume that this is 8 % of the initial total mass, then 24.9 % remains. The second stage should provide a Δv of 4.7 km/s; 1 − e − 4.7 / 4.5 = 0.648, therefore 64.8% of the remaining mass has to be propellant, which is 16.2 %, and 8.7 % remains for the tank and engines of the second stage, the payload, and in the case of a space shuttle, also the orbiter. Thus together 16.7 % is available for all engines, the tanks, the payload, and the possible orbiter.

A single-stage to orbit (or SSTO) launcher describes an as-yet theoretical class of spacecraft designed to place a load into orbit as a self-contained vehicle without the use of multiple stages. ... A two stage to orbit (or TSTO) launch vehicle is a spacecraft in which two distinct stages provide propulsion consecutively in order to achieve orbital velocity. ...

See also

General In general physics delta-v is simply the change in velocity. ... Delta-v budget (or velocity change budget) is a term used in astrodynamics and aerospace industry for velocity change (or delta-v) requirements for the various propulsive tasks and orbital maneuvers over phases of the space mission. ... The specific impulse (commonly abbreviated Isp) of a propulsion system is the impulse (change in momentum) per unit of propellant. ... A remote camera captures a close-up view of a Space Shuttle Main Engine during a test firing at the John C. Stennis Space Center in Hancock County, Mississippi Spacecraft propulsion is used to change the velocity of spacecraft and artificial satellites, or in short, to provide delta-v. ... In aerospace engineering, mass ratio is a measure of the proportion of a rocket that is propellant. ... Working mass is a mass against which a system operates in order to produce acceleration. ...

References

  1. ^ Johnson W., "Contents and commentary on William Moore's a treatise on the motion of rockets and an essay on naval gunnery", International Journal of Impact Engineering, Volume 16, Number 3, June 1995, pp. 499-521

  Results from FactBites:
 
Tsiolkovsky rocket equation - Wikipedia, the free encyclopedia (1466 words)
Tsiolkovsky's rocket equation, named after Konstantin Tsiolkovsky who independently derived it, considers the principle of a rocket: a device that can apply an acceleration to itself (a thrust) by expelling part of its mass with high speed in the opposite direction, due to the conservation of momentum.
This equation was independently derived by Konstantin Tsiolkovsky towards the end of the 19th century and is widely known under this name.
Thus the specific energy gain of the rocket in any small time interval is the energy gain of the rocket including the remaining fuel, divided by its mass, where the energy gain is equal to the energy produced by the fuel minus the energy gain of the reaction mass.
Top Literature - Rocket (2803 words)
A rocket is a vehicle, missile or aircraft which obtains thrust by the reaction to the ejection of fast moving exhaust gas from within a rocket engine.
Rockets must be used when there is no other substance (land, water, or air) or force (gravity, magnetism, light) that a vehicle may employ for propulsion, such as in space.
Rockets became extremely military important in the form of intercontinental ballistic missiles (ICBMs) when it was realised that nuclear weapons carried on a rocket vehicle were essentially not defensible against once launched, and they became the delivery platform of choice for these weapons.
  More results at FactBites »


 

COMMENTARY     


Share your thoughts, questions and commentary here
Your name
Your comments
Please enter the 5-letter protection code

Want to know more?
Search encyclopedia, statistics and forums:

 


Lesson Plans | Student Area | Student FAQ | Reviews | Press Releases |  Feeds | Contact
The Wikipedia article included on this page is licensed under the GFDL.
Images may be subject to relevant owners' copyright.
All other elements are (c) copyright NationMaster.com 2003-5. All Rights Reserved.
Usage implies agreement with terms.